skbio.tree.TreeNode.is_tip

TreeNode.is_tip()

Check if the current node is a tip of a tree.

Returns:

bool

Whether the node is a tip.

See also

is_root

has_children

Examples

>>> from skbio import TreeNode
>>> tree = TreeNode.read(["((a,b)c);"])
>>> print(tree.is_tip())
False
>>> print(tree.find('a').is_tip())
True