skbio.tree.TreeNode.is_tip

TreeNode.is_tip()

Return True if the current node has no children.

Returns:

bool

True if the node is a tip

See also

is_root

has_children

Examples

>>> from skbio import TreeNode
>>> tree = TreeNode.read(["((a,b)c);"])
>>> print(tree.is_tip())
False
>>> print(tree.find('a').is_tip())
True