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skbio.tree.TreeNode.is_tip#

TreeNode.is_tip()[source]#

Return True if the current node has no children.

Returns:
bool

True if the node is a tip

Examples

>>> from skbio import TreeNode
>>> tree = TreeNode.read(["((a,b)c);"])
>>> print(tree.is_tip())
False
>>> print(tree.find('a').is_tip())
True