skbio.tree.TreeNode.is_tip# TreeNode.is_tip()[source]# Check if the current node is a tip of a tree. Returns: boolWhether the node is a tip. See also is_root has_children Examples >>> from skbio import TreeNode >>> tree = TreeNode.read(["((a,b)c);"]) >>> print(tree.is_tip()) False >>> print(tree.find('a').is_tip()) True