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skbio.tree.TreeNode.has_children#

TreeNode.has_children()[source]#

Return True if the node has children.

Returns:
bool

True if the node has children.

See also

is_tip
is_root

Examples

>>> from skbio import TreeNode
>>> tree = TreeNode.read(["((a,b)c);"])
>>> print(tree.has_children())
True
>>> print(tree.find('a').has_children())
False