scikit-bio is back in active development! Check out our announcement of revitalization.

skbio.tree.TreeNode.is_root#

TreeNode.is_root()[source]#

Return True if the current is a root, i.e. has no parent.

Returns:
bool

True if the node is the root

See also

is_tip
has_children

Examples

>>> from skbio import TreeNode
>>> tree = TreeNode.read(["((a,b)c);"])
>>> print(tree.is_root())
True
>>> print(tree.find('a').is_root())
False